2m^2-20m-24=0

Solution for 2m^2-20m-24=0 equation:

2m^2-20m-24=0

a = 2; b = -20; c = -24;
Δ = b2-4ac
Δ = -202-4·2·(-24)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{37}}{2*2}=\frac{20-4\sqrt{37}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{37}}{2*2}=\frac{20+4\sqrt{37}}{4}
$